Recap: The basic idea of the game is that player 1 chases player 2 on a circular board. If player 1 catches player 2 within twenty rounds, player 1 wins.
I have a policy of giving free link love to any bloggers that post good solutions. This time, Hugo of thinktoomuch.net wins! (Hugo's blog, by the way, has become a new favorite of mine.) Here's his solution:
Call the middle "ring 0", the next "ring 1", the outer is "ring 4".Allow me to illustrate this solution:
If player 2 is in ring N, player 1 wants to be in ring N-1, always moving to a place that is adjacent to player 2's position. Player 2 can race around and around in ring N, with player 1 chasing in ring N-1, only until it gets to the point where player 1 is in the N-1 region that is adjacent to 3 N regions. That forces player 2 to go to ring N+1.
To start, player 1 goes to ring 0, from there heading out to get adjacent to player 2. To finish, player 1 traps player 2 in ring 4, at the bottom.
As long as player 1 stays one ring closer to the center, player 2 will eventually be forced outwards. When player 1 is in the cyan region and player 2 in the corresponding blue region, player 2 will have no choice to move outwards. When player 2 is stuck in the outermost blue region, the game is over.
Hugo also said:
New question: what's the maximum number of moves that player 2 can survive? I believe it would have player 1 on ring 4 to begin with, and player 2 playing in a way that player 1 has to chase player 2 all the way around every ring. I've not counted, but I place my bets on player 2 if player 1 only gets 20 moves.Here, I admit to making a "mistake" in writing this puzzle. I meant to give player 1 plenty of time, but in a lapse of judgment I limited it to 20 moves. Player 1 might not be able to win that quickly! But regardless of my original intention, it is still an interesting question. I am not sure of the answer, but here are my rambling thoughts on the matter. I welcome any proofs you can come up with.
We can put some upper bounds on the number of moves required:
- 4 moves to get to ring 0.
- 3 moves to force player 2 to ring 2.
- 5 moves to force player 2 to ring 3.
- 6 moves to force player 2 to ring 4.
- 7 moves to trap player 2 at the bottom.
- 1 move to win.
One way to reduce them is by saying that the first player can choose which direction to go around the rings. This would reduce the number of required moves to maybe 18 or less. However, there is a way for player 2 to choose the direction, if player 2 jumps to the next ring before being forced to. I found a 21-move path in which player 2 constantly forces the direction to be clockwise. That's enough for player 2 to win! To win this way, allow 4 moves for player 1 to reach the cyan region below, and then run along the red path for 16 moves.
However, this path only works if player 1 strictly follows the strategy of remaining adjacent to player 2 at all times. I suspect that player 1 can slightly modify his strategy and win.
This game turns out to be more complicated than I thought.