Sunday, February 6, 2011

Solutions to circular cutouts

See the original puzzle

Above, I've highlighted several regions which we will use as intermediate steps to find the area of the center.  The letters A through D represent the area of that region.  I'm taking the square to have unit length sides.

A is a sixth of a circle.
A = 1/6 pi

B is an equilateral triangle.
B = sqrt(3)/4

C can be found by combining A and B.
C = 2A - B = 1/3 pi - sqrt(3)/4

D is a quarter of a circle.
D = 1/4 pi

By tinkering around with C and D, we can find the area of the center region.
Area of center = 1 - 4D + 4C = 1/3 pi + 1 - sqrt(3)